By Pierre Fortin

ISBN-10: 2764424221

ISBN-13: 9782764424223

Jean Landry, professeur de photographie à l’Université du Québec à Montréal, est retrouvé dans un état frisant los angeles catatonie. Pourquoi ne réagit-il plus? Un seul individu sait vraiment ce qui s’est passé. Il s’agit de Paul Garant.

Ainsi s’amorce le récit de l’ami qui raconte à Michèle, los angeles fille de Jean, ce qui a mené son père à cet état. Nourri par sa quête de savoir frisant l’obsession, Paul lui raconte tout à l’aide des informations qu’il a glanées dans le magazine group of workers de Jean et par ses propres observations.

Il y a, entre autres, cette histoire d’un étrange collectionneur qui s’est approprié les photographs, textes et records de Jean et qui les a disséminés en les revendant à des brocanteurs et des galéristes. Il y a aussi les difficiles family amoureuses de Jean. Même los angeles marche, qui lui servait d’exutoire, ne lui procurerait plus los angeles tranquillité d’esprit si nécessaire à son équilibre. Sentant qu’il ne s’appartenait plus, Jean a glissé dans un monde où los angeles paranoïa nourrissait son quotidien.

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Hence ε(x, t) = q2 , 2t j(x, t) = q2x x = ε(x, t). 4 39 Equivalence to Nonlinear Schr¨ odinger Equations 1. 1) as e1t = e1 × e . 38) −2 τ (x, t) = k e1 · (e1 × e1 ). 39) Now establish an orthogonal three-side-body e1 , e2 , e3 where e2 lies along the direction of e1 , e3 = e1 × e2 . 40)   e3 = −τ e3 . 41) e3 , j = 1, 2, 3. 42) These conditions lead to the following equations of k and τ :    kt = −2kx τ − kτx ,     τt = kxx − τ2 k + kk . 44) where ε = 21 | ∂∂xS |2 , j(x, t) = S · (Sx × Sxx ) and 1 ε(x, t) = x2 , 2 j(x, t) = k 2 τ.

18), we have Z(Z + y 2 ) = 0. 22) Z + y 2 = 2(α − ΩZ)(1 − Z 2 ). 23) Z − cy − 3ΩZ 2 + 2αZ + Ω = 0. 22). 25) 1 α = Ω = c2 . 26) dϕ c = . 20) that Landau–Lifshitz Equations 38 Then we have by integrating this equation that 1 1 ϕ = tan−1 tanh cu + cu. 3 j(u) = cε(u). e. 1 η = xt− 2 . 31) η S = −2S × S . 33) with |S (η)| = q. 32) j(x, t) = η |S (η)|2 . 32) that S · S = 0, we get |S (η)|2 = q 2 = constant. Hence ε(x, t) = q2 , 2t j(x, t) = q2x x = ε(x, t). 4 39 Equivalence to Nonlinear Schr¨ odinger Equations 1.

In order to derive the resonance conditions, we take Laurant expansion aj ϕj−1 , a= j bj ϕj−1 , b= ϕj−1 . 16), we get the matrix equation for the coefficients of the terms with lower order as    (j 2 − 3j)ϕ2r 0 2a0 aj    2 2    0 (j − 3j)ϕr 2b0     bj  = 0. 19) that the resonance conditions are j = −1, 0, 2, 3, 4. 22) Landau–Lifshitz Equations 48 Obviously, resonance j = −1 implies the arbitrariness of the singular flow ϕ(x, t) = 0, resonance j = 0 indicates the arbitrariness of the functions a0 or b0 .

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Le Marcheur by Pierre Fortin


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